0=-2.78t^2+36t+2.4

Solution for 0=-2.78t^2+36t+2.4 equation:

0=-2.78t^2+36t+2.4

We move all terms to the left:

0-(-2.78t^2+36t+2.4)=0

We add all the numbers together, and all the variables

-(-2.78t^2+36t+2.4)=0

We get rid of parentheses

2.78t^2-36t-2.4=0

a = 2.78; b = -36; c = -2.4;
Δ = b2-4ac
Δ = -362-4·2.78·(-2.4)
Δ = 1322.688
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-\sqrt{1322.688}}{2*2.78}=\frac{36-\sqrt{1322.688}}{5.56}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+\sqrt{1322.688}}{2*2.78}=\frac{36+\sqrt{1322.688}}{5.56}
$